PSLEBen had a number of bracelets for sale. He sold a total of 540 bracelets on Monday and Tuesday. On Wednesday, he sold
15 of the remainder. He was left with 8% of the bracelets he had at first. How many bracelets did he have at first?
Monday |
Tuesday |
Remainder |
540 |
Wednesday |
Left |
|
|
1 u |
4 u |
90%
|
2% |
8% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total bracelets sold on Wednesday
= 8% ÷ 4
= 2%
Percent of total bracelets sold on Monday and Tuesday
= 100% - 8% - 2%
= 90%
90% = 540
1% = 540 ÷ 90 = 6
Total number of bracelets at first
= 100%
= 100 x 6
= 600
Answer(s): 600