PSLEPaul had a number of bracelets for sale. He sold a total of 504 bracelets on Tuesday and Wednesday. On Thursday, he sold
14 of the remainder. He was left with 12% of the bracelets he had at first. How many bracelets did he have at first?
Tuesday |
Wednesday |
Remainder |
504 |
Thursday |
Left |
|
|
1 u |
3 u |
84%
|
4% |
12% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total bracelets sold on Thursday
= 12% ÷ 3
= 4%
Percent of total bracelets sold on Tuesday and Wednesday
= 100% - 12% - 4%
= 84%
84% = 504
1% = 504 ÷ 84 = 6
Total number of bracelets at first
= 100%
= 100 x 6
= 600
Answer(s): 600