PSLEAsher had a number of bracelets for sale. He sold a total of 672 bracelets on Wednesday and Thursday. On Friday, he sold
14 of the remainder. He was left with 12% of the bracelets he had at first. How many bracelets did he have at first?
Wednesday |
Thursday |
Remainder |
672 |
Friday |
Left |
|
|
1 u |
3 u |
84%
|
4% |
12% |
Fraction of the remainder left
= 1 -
14 =
34Percent of total bracelets sold on Friday
= 12% ÷ 3
= 4%
Percent of total bracelets sold on Wednesday and Thursday
= 100% - 12% - 4%
= 84%
84% = 672
1% = 672 ÷ 84 = 8
Total number of bracelets at first
= 100%
= 100 x 8
= 800
Answer(s): 800