PSLEGeorge had a number of bracelets for sale. He sold a total of 240 bracelets on Wednesday and Thursday. On Friday, he sold
15 of the remainder. He was left with 16% of the bracelets he had at first. How many bracelets did he have at first?
Wednesday |
Thursday |
Remainder |
240 |
Friday |
Left |
|
|
1 u |
4 u |
80%
|
4% |
16% |
Fraction of the remainder left
= 1 -
15 =
45Percent of total bracelets sold on Friday
= 16% ÷ 4
= 4%
Percent of total bracelets sold on Wednesday and Thursday
= 100% - 16% - 4%
= 80%
80% = 240
1% = 240 ÷ 80 = 3
Total number of bracelets at first
= 100%
= 100 x 3
= 300
Answer(s): 300