Howard has $20. Charlie has $4
z more than Howard. Ken has $2
z less than Charlie.
- Find the amount of money that Ken has in terms of z.
- Find the total amount of money that the three boys have in terms of z.
- If z = 5, how much does Ken have?
(a)
Amount that Howard has = $20
Amount that Charlie has = $(20 + 4
z)
Amount that Ken has
= 20 + 4
z - 2
z = $(20 + 2
z)
(b)
Total amount that the three boys have
= 20 + 20 + 4
z + 20 + 2
z= 20 + 20 + 20 + 4
z + 2
z = $(60 + 6
z)
(c)
Amount that Ken has
= 20 + 2
z= 20 + 2 x 5
= 20 + 10
= $30
Answer(s): (a) $(20 + 2
z) or $(2
z + 20); (b) $(60 + 6
z) or $(6
z + 60); (c) $30