Cole has $19. Eric has $5
k more than Cole. Pierre has $2
k less than Eric.
- Find the amount of money that Pierre has in terms of k.
- Find the total amount of money that the three boys have in terms of k.
- If k = 5, how much does Pierre have?
(a)
Amount that Cole has = $19
Amount that Eric has = $(19 + 5
k)
Amount that Pierre has
= 19 + 5
k - 2
k = $(19 + 3
k)
(b)
Total amount that the three boys have
= 19 + 19 + 5
k + 19 + 3
k= 19 + 19 + 19 + 5
k + 3
k = $(57 + 8
k)
(c)
Amount that Pierre has
= 19 + 3
k= 19 + 3 x 5
= 19 + 15
= $34
Answer(s): (a) $(19 + 3
k) or $(3
k + 19); (b) $(57 + 8
k) or $(8
k + 57); (c) $34