Lee has $16. Warren has $4
i more than Lee. Sean has $2
i less than Warren.
- Find the amount of money that Sean has in terms of i.
- Find the total amount of money that the three boys have in terms of i.
- If i = 6, how much does Sean have?
(a)
Amount that Lee has = $16
Amount that Warren has = $(16 + 4
i)
Amount that Sean has
= 16 + 4
i - 2
i = $(16 + 2
i)
(b)
Total amount that the three boys have
= 16 + 16 + 4
i + 16 + 2
i= 16 + 16 + 16 + 4
i + 2
i = $(48 + 6
i)
(c)
Amount that Sean has
= 16 + 2
i= 16 + 2 x 6
= 16 + 12
= $28
Answer(s): (a) $(16 + 2
i) or $(2
i + 16); (b) $(48 + 6
i) or $(6
i + 48); (c) $28