Zane has $10. Albert has $4
d more than Zane. Ken has $2
d less than Albert.
- Find the amount of money that Ken has in terms of d.
- Find the total amount of money that the three boys have in terms of d.
- If d = 6, how much does Ken have?
(a)
Amount that Zane has = $10
Amount that Albert has = $(10 + 4
d)
Amount that Ken has
= 10 + 4
d - 2
d = $(10 + 2
d)
(b)
Total amount that the three boys have
= 10 + 10 + 4
d + 10 + 2
d= 10 + 10 + 10 + 4
d + 2
d = $(30 + 6
d)
(c)
Amount that Ken has
= 10 + 2
d= 10 + 2 x 6
= 10 + 12
= $22
Answer(s): (a) $(10 + 2
d) or $(2
d + 10); (b) $(30 + 6
d) or $(6
d + 30); (c) $22