Howard has $20. Lee has $5
h more than Howard. Pierre has $2
h less than Lee.
- Find the amount of money that Pierre has in terms of h.
- Find the total amount of money that the three boys have in terms of h.
- If h = 7, how much does Pierre have?
(a)
Amount that Howard has = $20
Amount that Lee has = $(20 + 5
h)
Amount that Pierre has
= 20 + 5
h - 2
h = $(20 + 3
h)
(b)
Total amount that the three boys have
= 20 + 20 + 5
h + 20 + 3
h= 20 + 20 + 20 + 5
h + 3
h = $(60 + 8
h)
(c)
Amount that Pierre has
= 20 + 3
h= 20 + 3 x 7
= 20 + 21
= $41
Answer(s): (a) $(20 + 3
h) or $(3
h + 20); (b) $(60 + 8
h) or $(8
h + 60); (c) $41