Michael has $17. Dylan has $4
z more than Michael. Seth has $2
z less than Dylan.
- Find the amount of money that Seth has in terms of z.
- Find the total amount of money that the three boys have in terms of z.
- If z = 7, how much does Seth have?
(a)
Amount that Michael has = $17
Amount that Dylan has = $(17 + 4
z)
Amount that Seth has
= 17 + 4
z - 2
z = $(17 + 2
z)
(b)
Total amount that the three boys have
= 17 + 17 + 4
z + 17 + 2
z= 17 + 17 + 17 + 4
z + 2
z = $(51 + 6
z)
(c)
Amount that Seth has
= 17 + 2
z= 17 + 2 x 7
= 17 + 14
= $31
Answer(s): (a) $(17 + 2
z) or $(2
z + 17); (b) $(51 + 6
z) or $(6
z + 51); (c) $31