Bryan has $10. Zeph has $4
n more than Bryan. Mark has $2
n less than Zeph.
- Find the amount of money that Mark has in terms of n.
- Find the total amount of money that the three boys have in terms of n.
- If n = 6, how much does Mark have?
(a)
Amount that Bryan has = $10
Amount that Zeph has = $(10 + 4
n)
Amount that Mark has
= 10 + 4
n - 2
n = $(10 + 2
n)
(b)
Total amount that the three boys have
= 10 + 10 + 4
n + 10 + 2
n= 10 + 10 + 10 + 4
n + 2
n = $(30 + 6
n)
(c)
Amount that Mark has
= 10 + 2
n= 10 + 2 x 6
= 10 + 12
= $22
Answer(s): (a) $(10 + 2
n) or $(2
n + 10); (b) $(30 + 6
n) or $(6
n + 30); (c) $22