Harry has $14. Cody has $4
y more than Harry. Cole has $2
y less than Cody.
- Find the amount of money that Cole has in terms of y.
- Find the total amount of money that the three boys have in terms of y.
- If y = 4, how much does Cole have?
(a)
Amount that Harry has = $14
Amount that Cody has = $(14 + 4
y)
Amount that Cole has
= 14 + 4
y - 2
y = $(14 + 2
y)
(b)
Total amount that the three boys have
= 14 + 14 + 4
y + 14 + 2
y= 14 + 14 + 14 + 4
y + 2
y = $(42 + 6
y)
(c)
Amount that Cole has
= 14 + 2
y= 14 + 2 x 4
= 14 + 8
= $22
Answer(s): (a) $(14 + 2
y) or $(2
y + 14); (b) $(42 + 6
y) or $(6
y + 42); (c) $22