Lui has $16. Peter has $4
z more than Lui. Pierre has $2
z less than Peter.
- Find the amount of money that Pierre has in terms of z.
- Find the total amount of money that the three boys have in terms of z.
- If z = 4, how much does Pierre have?
(a)
Amount that Lui has = $16
Amount that Peter has = $(16 + 4
z)
Amount that Pierre has
= 16 + 4
z - 2
z = $(16 + 2
z)
(b)
Total amount that the three boys have
= 16 + 16 + 4
z + 16 + 2
z= 16 + 16 + 16 + 4
z + 2
z = $(48 + 6
z)
(c)
Amount that Pierre has
= 16 + 2
z= 16 + 2 x 4
= 16 + 8
= $24
Answer(s): (a) $(16 + 2
z) or $(2
z + 16); (b) $(48 + 6
z) or $(6
z + 48); (c) $24