Peter has $18. Bobby has $4
i more than Peter. Sean has $2
i less than Bobby.
- Find the amount of money that Sean has in terms of i.
- Find the total amount of money that the three boys have in terms of i.
- If i = 6, how much does Sean have?
(a)
Amount that Peter has = $18
Amount that Bobby has = $(18 + 4
i)
Amount that Sean has
= 18 + 4
i - 2
i = $(18 + 2
i)
(b)
Total amount that the three boys have
= 18 + 18 + 4
i + 18 + 2
i= 18 + 18 + 18 + 4
i + 2
i = $(54 + 6
i)
(c)
Amount that Sean has
= 18 + 2
i= 18 + 2 x 6
= 18 + 12
= $30
Answer(s): (a) $(18 + 2
i) or $(2
i + 18); (b) $(54 + 6
i) or $(6
i + 54); (c) $30