Dylan has $9. Brandon has $4
e more than Dylan. Cole has $2
e less than Brandon.
- Find the amount of money that Cole has in terms of e.
- Find the total amount of money that the three boys have in terms of e.
- If e = 6, how much does Cole have?
(a)
Amount that Dylan has = $9
Amount that Brandon has = $(9 + 4
e)
Amount that Cole has
= 9 + 4
e - 2
e = $(9 + 2
e)
(b)
Total amount that the three boys have
= 9 + 9 + 4
e + 9 + 2
e= 9 + 9 + 9 + 4
e + 2
e = $(27 + 6
e)
(c)
Amount that Cole has
= 9 + 2
e= 9 + 2 x 6
= 9 + 12
= $21
Answer(s): (a) $(9 + 2
e) or $(2
e + 9); (b) $(27 + 6
e) or $(6
e + 27); (c) $21