Reggie has $20. Xavier has $5
i more than Reggie. Charlie has $2
i less than Xavier.
- Find the amount of money that Charlie has in terms of i.
- Find the total amount of money that the three boys have in terms of i.
- If i = 6, how much does Charlie have?
(a)
Amount that Reggie has = $20
Amount that Xavier has = $(20 + 5
i)
Amount that Charlie has
= 20 + 5
i - 2
i = $(20 + 3
i)
(b)
Total amount that the three boys have
= 20 + 20 + 5
i + 20 + 3
i= 20 + 20 + 20 + 5
i + 3
i = $(60 + 8
i)
(c)
Amount that Charlie has
= 20 + 3
i= 20 + 3 x 6
= 20 + 18
= $38
Answer(s): (a) $(20 + 3
i) or $(3
i + 20); (b) $(60 + 8
i) or $(8
i + 60); (c) $38