Cody has $20. Jeremy has $5
j more than Cody. Lee has $2
j less than Jeremy.
- Find the amount of money that Lee has in terms of j.
- Find the total amount of money that the three boys have in terms of j.
- If j = 6, how much does Lee have?
(a)
Amount that Cody has = $20
Amount that Jeremy has = $(20 + 5
j)
Amount that Lee has
= 20 + 5
j - 2
j = $(20 + 3
j)
(b)
Total amount that the three boys have
= 20 + 20 + 5
j + 20 + 3
j= 20 + 20 + 20 + 5
j + 3
j = $(60 + 8
j)
(c)
Amount that Lee has
= 20 + 3
j= 20 + 3 x 6
= 20 + 18
= $38
Answer(s): (a) $(20 + 3
j) or $(3
j + 20); (b) $(60 + 8
j) or $(8
j + 60); (c) $38