Pierre saved $10 each day and Hazel saved $
r more than Pierre each day. After 6 weeks, they were still short of $30 to buy a tablet.
- How much did the tablet cost? Express your answer in terms of r.
- If r = $10, how much did the tablet cost?
(a)
Amount Pierre saved per day = $10
Amount Hazel saved per day = $(10 +
r)
Total amount both saved per day
= 10 + 10 +
r = $(20 +
r)
Number of days in 6 weeks
= 6 x 7
= 42
Total both saved in 6 weeks
= 42(20 +
r)
= 42 x 20 + 42 x
r = $(840 + 42
r)
Cost of the tablet
= 840 + 42
r + 30
= 840 + 30 + 42
r= $(870 + 42
r)
(b)
If
r = $10,
Cost of the tablet
= 870 + 42 x 10
= 870 + 420
= $1290
Answer(s): (a) $(870 + 42
r) or $(42
r + 870); (b) $1290
