Xavier is
p years old. Charlie is six times as old as Xavier and Simon is 5 years younger than Charlie.
- Express Simon's age in terms of p.
- Xavier is 7 years old as of now. ln how many years' time will Simon be 4 times as old as Xavier?
(a)
Xavier's age =
p years
Charlie's age = 6
p years
Simon's age = (6
p - 5) years
(b)
p = 7
Difference in age remains unchanged.
Difference in age between Simon and Xavier
= (6
p - 5) -
p = 6
p -
p - 5
= 5
p - 5
= 5 x 7 - 5
= 30 years
Difference in the age when Simon will be 4 times as old as Xavier
= 4 u - 1 u
= 3 u
3 u = 30
1 u = 30 ÷ 3 = 10
Number of years' time so Simon will be 4 times as old as Xavier
= 10 - 7
= 3 years
Answer(s): (a) (6
p - 5) years; (b) 3 years
