Luke is
z years old. Michael is six times as old as Luke and Simon is 12 years younger than Michael.
- Express Simon's age in terms of z.
- Luke is 8 years old as of now. ln how many years' time will Simon be 3 times as old as Luke?
(a)
Luke's age =
z years
Michael's age = 6
z years
Simon's age = (6
z - 12) years
(b)
z = 8
Difference in age remains unchanged.
Difference in age between Simon and Luke
= (6
z - 12) -
z = 6
z -
z - 12
= 5
z - 12
= 5 x 8 - 12
= 28 years
Difference in the age when Simon will be 3 times as old as Luke
= 3 u - 1 u
= 2 u
2 u = 28
1 u = 28 ÷ 2 = 14
Number of years' time so Simon will be 3 times as old as Luke
= 14 - 8
= 6 years
Answer(s): (a) (6
z - 12) years; (b) 6 years
