Julian is
c years old. John is six times as old as Julian and Neave is 9 years younger than John.
- Express Neave's age in terms of c.
- Julian is 9 years old as of now. ln how many years' time will Neave be 3 times as old as Julian?
(a)
Julian's age =
c years
John's age = 6
c years
Neave's age = (6
c - 9) years
(b)
c = 9
Difference in age remains unchanged.
Difference in age between Neave and Julian
= (6
c - 9) -
c = 6
c -
c - 9
= 5
c - 9
= 5 x 9 - 9
= 36 years
Difference in the age when Neave will be 3 times as old as Julian
= 3 u - 1 u
= 2 u
2 u = 36
1 u = 36 ÷ 2 = 18
Number of years' time so Neave will be 3 times as old as Julian
= 18 - 9
= 9 years
Answer(s): (a) (6
c - 9) years; (b) 9 years
