Mark is
p years old. Elijah is six times as old as Mark and Howard is 9 years younger than Elijah.
- Express Howard's age in terms of p.
- Mark is 9 years old as of now. ln how many years' time will Howard be 4 times as old as Mark?
(a)
Mark's age =
p years
Elijah's age = 6
p years
Howard's age = (6
p - 9) years
(b)
p = 9
Difference in age remains unchanged.
Difference in age between Howard and Mark
= (6
p - 9) -
p = 6
p -
p - 9
= 5
p - 9
= 5 x 9 - 9
= 36 years
Difference in the age when Howard will be 4 times as old as Mark
= 4 u - 1 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Number of years' time so Howard will be 4 times as old as Mark
= 12 - 9
= 3 years
Answer(s): (a) (6
p - 9) years; (b) 3 years
