Cody is
w years old. Bobby is six times as old as Cody and Lee is 8 years younger than Bobby.
- Express Lee's age in terms of w.
- Cody is 7 years old as of now. ln how many years' time will Lee be 4 times as old as Cody?
(a)
Cody's age =
w years
Bobby's age = 6
w years
Lee's age = (6
w - 8) years
(b)
w = 7
Difference in age remains unchanged.
Difference in age between Lee and Cody
= (6
w - 8) -
w = 6
w -
w - 8
= 5
w - 8
= 5 x 7 - 8
= 27 years
Difference in the age when Lee will be 4 times as old as Cody
= 4 u - 1 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of years' time so Lee will be 4 times as old as Cody
= 9 - 7
= 2 years
Answer(s): (a) (6
w - 8) years; (b) 2 years
