Reggie is
i years old. Michael is six times as old as Reggie and Fred is 12 years younger than Michael.
- Express Fred's age in terms of i.
- Reggie is 10 years old as of now. ln how many years' time will Fred be 3 times as old as Reggie?
(a)
Reggie's age =
i years
Michael's age = 6
i years
Fred's age = (6
i - 12) years
(b)
i = 10
Difference in age remains unchanged.
Difference in age between Fred and Reggie
= (6
i - 12) -
i = 6
i -
i - 12
= 5
i - 12
= 5 x 10 - 12
= 38 years
Difference in the age when Fred will be 3 times as old as Reggie
= 3 u - 1 u
= 2 u
2 u = 38
1 u = 38 ÷ 2 = 19
Number of years' time so Fred will be 3 times as old as Reggie
= 19 - 10
= 9 years
Answer(s): (a) (6
i - 12) years; (b) 9 years
