Luke is
w years old. Paul is six times as old as Luke and Neave is 10 years younger than Paul.
- Express Neave's age in terms of w.
- Luke is 6 years old as of now. ln how many years' time will Neave be 3 times as old as Luke?
(a)
Luke's age =
w years
Paul's age = 6
w years
Neave's age = (6
w - 10) years
(b)
w = 6
Difference in age remains unchanged.
Difference in age between Neave and Luke
= (6
w - 10) -
w = 6
w -
w - 10
= 5
w - 10
= 5 x 6 - 10
= 20 years
Difference in the age when Neave will be 3 times as old as Luke
= 3 u - 1 u
= 2 u
2 u = 20
1 u = 20 ÷ 2 = 10
Number of years' time so Neave will be 3 times as old as Luke
= 10 - 6
= 4 years
Answer(s): (a) (6
w - 10) years; (b) 4 years
