Simon is
d years old. Will is five times as old as Simon and David is 4 years younger than Will.
- Express David's age in terms of d.
- Simon is 4 years old as of now. ln how many years' time will David be 3 times as old as Simon?
(a)
Simon's age =
d years
Will's age = 5
d years
David's age = (5
d - 4) years
(b)
d = 4
Difference in age remains unchanged.
Difference in age between David and Simon
= (5
d - 4) -
d = 5
d -
d - 4
= 4
d - 4
= 4 x 4 - 4
= 12 years
Difference in the age when David will be 3 times as old as Simon
= 3 u - 1 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of years' time so David will be 3 times as old as Simon
= 6 - 4
= 2 years
Answer(s): (a) (5
d - 4) years; (b) 2 years
