Michael is
k years old. Daniel is six times as old as Michael and Albert is 11 years younger than Daniel.
- Express Albert's age in terms of k.
- Michael is 5 years old as of now. ln how many years' time will Albert be 3 times as old as Michael?
(a)
Michael's age =
k years
Daniel's age = 6
k years
Albert's age = (6
k - 11) years
(b)
k = 5
Difference in age remains unchanged.
Difference in age between Albert and Michael
= (6
k - 11) -
k = 6
k -
k - 11
= 5
k - 11
= 5 x 5 - 11
= 14 years
Difference in the age when Albert will be 3 times as old as Michael
= 3 u - 1 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of years' time so Albert will be 3 times as old as Michael
= 7 - 5
= 2 years
Answer(s): (a) (6
k - 11) years; (b) 2 years
