Gabriel is
d years old. Ken is six times as old as Gabriel and George is 5 years younger than Ken.
- Express George's age in terms of d.
- Gabriel is 3 years old as of now. ln how many years' time will George be 3 times as old as Gabriel?
(a)
Gabriel's age =
d years
Ken's age = 6
d years
George's age = (6
d - 5) years
(b)
d = 3
Difference in age remains unchanged.
Difference in age between George and Gabriel
= (6
d - 5) -
d = 6
d -
d - 5
= 5
d - 5
= 5 x 3 - 5
= 10 years
Difference in the age when George will be 3 times as old as Gabriel
= 3 u - 1 u
= 2 u
2 u = 10
1 u = 10 ÷ 2 = 5
Number of years' time so George will be 3 times as old as Gabriel
= 5 - 3
= 2 years
Answer(s): (a) (6
d - 5) years; (b) 2 years
