Mark is
y years old. Jenson is six times as old as Mark and Vaidev is 5 years younger than Jenson.
- Express Vaidev's age in terms of y.
- Mark is 9 years old as of now. ln how many years' time will Vaidev be 3 times as old as Mark?
(a)
Mark's age =
y years
Jenson's age = 6
y years
Vaidev's age = (6
y - 5) years
(b)
y = 9
Difference in age remains unchanged.
Difference in age between Vaidev and Mark
= (6
y - 5) -
y = 6
y -
y - 5
= 5
y - 5
= 5 x 9 - 5
= 40 years
Difference in the age when Vaidev will be 3 times as old as Mark
= 3 u - 1 u
= 2 u
2 u = 40
1 u = 40 ÷ 2 = 20
Number of years' time so Vaidev will be 3 times as old as Mark
= 20 - 9
= 11 years
Answer(s): (a) (6
y - 5) years; (b) 11 years
