Gabriel is
x years old. Harry is six times as old as Gabriel and Cody is 11 years younger than Harry.
- Express Cody's age in terms of x.
- Gabriel is 5 years old as of now. ln how many years' time will Cody be 3 times as old as Gabriel?
(a)
Gabriel's age =
x years
Harry's age = 6
x years
Cody's age = (6
x - 11) years
(b)
x = 5
Difference in age remains unchanged.
Difference in age between Cody and Gabriel
= (6
x - 11) -
x = 6
x -
x - 11
= 5
x - 11
= 5 x 5 - 11
= 14 years
Difference in the age when Cody will be 3 times as old as Gabriel
= 3 u - 1 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Number of years' time so Cody will be 3 times as old as Gabriel
= 7 - 5
= 2 years
Answer(s): (a) (6
x - 11) years; (b) 2 years
