Cody is
s years old. Xavier is six times as old as Cody and Dylan is 8 years younger than Xavier.
- Express Dylan's age in terms of s.
- Cody is 10 years old as of now. ln how many years' time will Dylan be 4 times as old as Cody?
(a)
Cody's age =
s years
Xavier's age = 6
s years
Dylan's age = (6
s - 8) years
(b)
s = 10
Difference in age remains unchanged.
Difference in age between Dylan and Cody
= (6
s - 8) -
s = 6
s -
s - 8
= 5
s - 8
= 5 x 10 - 8
= 42 years
Difference in the age when Dylan will be 4 times as old as Cody
= 4 u - 1 u
= 3 u
3 u = 42
1 u = 42 ÷ 3 = 14
Number of years' time so Dylan will be 4 times as old as Cody
= 14 - 10
= 4 years
Answer(s): (a) (6
s - 8) years; (b) 4 years
