Peter is
q years old. Cody is five times as old as Peter and Ken is 4 years younger than Cody.
- Express Ken's age in terms of q.
- Peter is 4 years old as of now. ln how many years' time will Ken be 3 times as old as Peter?
(a)
Peter's age =
q years
Cody's age = 5
q years
Ken's age = (5
q - 4) years
(b)
q = 4
Difference in age remains unchanged.
Difference in age between Ken and Peter
= (5
q - 4) -
q = 5
q -
q - 4
= 4
q - 4
= 4 x 4 - 4
= 12 years
Difference in the age when Ken will be 3 times as old as Peter
= 3 u - 1 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of years' time so Ken will be 3 times as old as Peter
= 6 - 4
= 2 years
Answer(s): (a) (5
q - 4) years; (b) 2 years
