Neave is
h years old. Luke is six times as old as Neave and Brandon is 14 years younger than Luke.
- Express Brandon's age in terms of h.
- Neave is 10 years old as of now. ln how many years' time will Brandon be 4 times as old as Neave?
(a)
Neave's age =
h years
Luke's age = 6
h years
Brandon's age = (6
h - 14) years
(b)
h = 10
Difference in age remains unchanged.
Difference in age between Brandon and Neave
= (6
h - 14) -
h = 6
h -
h - 14
= 5
h - 14
= 5 x 10 - 14
= 36 years
Difference in the age when Brandon will be 4 times as old as Neave
= 4 u - 1 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Number of years' time so Brandon will be 4 times as old as Neave
= 12 - 10
= 2 years
Answer(s): (a) (6
h - 14) years; (b) 2 years
