Xavier is
x years old. Ben is five times as old as Xavier and Ian is 8 years younger than Ben.
- Express Ian's age in terms of x.
- Xavier is 6 years old as of now. ln how many years' time will Ian be 3 times as old as Xavier?
(a)
Xavier's age =
x years
Ben's age = 5
x years
Ian's age = (5
x - 8) years
(b)
x = 6
Difference in age remains unchanged.
Difference in age between Ian and Xavier
= (5
x - 8) -
x = 5
x -
x - 8
= 4
x - 8
= 4 x 6 - 8
= 16 years
Difference in the age when Ian will be 3 times as old as Xavier
= 3 u - 1 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Number of years' time so Ian will be 3 times as old as Xavier
= 8 - 6
= 2 years
Answer(s): (a) (5
x - 8) years; (b) 2 years
