Xavier is
f years old. Jenson is five times as old as Xavier and Fred is 4 years younger than Jenson.
- Express Fred's age in terms of f.
- Xavier is 9 years old as of now. ln how many years' time will Fred be 3 times as old as Xavier?
(a)
Xavier's age =
f years
Jenson's age = 5
f years
Fred's age = (5
f - 4) years
(b)
f = 9
Difference in age remains unchanged.
Difference in age between Fred and Xavier
= (5
f - 4) -
f = 5
f -
f - 4
= 4
f - 4
= 4 x 9 - 4
= 32 years
Difference in the age when Fred will be 3 times as old as Xavier
= 3 u - 1 u
= 2 u
2 u = 32
1 u = 32 ÷ 2 = 16
Number of years' time so Fred will be 3 times as old as Xavier
= 16 - 9
= 7 years
Answer(s): (a) (5
f - 4) years; (b) 7 years
