Cole is
m years old. Xavier is six times as old as Cole and Owen is 14 years younger than Xavier.
- Express Owen's age in terms of m.
- Cole is 10 years old as of now. ln how many years' time will Owen be 3 times as old as Cole?
(a)
Cole's age =
m years
Xavier's age = 6
m years
Owen's age = (6
m - 14) years
(b)
m = 10
Difference in age remains unchanged.
Difference in age between Owen and Cole
= (6
m - 14) -
m = 6
m -
m - 14
= 5
m - 14
= 5 x 10 - 14
= 36 years
Difference in the age when Owen will be 3 times as old as Cole
= 3 u - 1 u
= 2 u
2 u = 36
1 u = 36 ÷ 2 = 18
Number of years' time so Owen will be 3 times as old as Cole
= 18 - 10
= 8 years
Answer(s): (a) (6
m - 14) years; (b) 8 years
