Will is
e years old. Caden is six times as old as Will and David is 9 years younger than Caden.
- Express David's age in terms of e.
- Will is 9 years old as of now. ln how many years' time will David be 4 times as old as Will?
(a)
Will's age =
e years
Caden's age = 6
e years
David's age = (6
e - 9) years
(b)
e = 9
Difference in age remains unchanged.
Difference in age between David and Will
= (6
e - 9) -
e = 6
e -
e - 9
= 5
e - 9
= 5 x 9 - 9
= 36 years
Difference in the age when David will be 4 times as old as Will
= 4 u - 1 u
= 3 u
3 u = 36
1 u = 36 ÷ 3 = 12
Number of years' time so David will be 4 times as old as Will
= 12 - 9
= 3 years
Answer(s): (a) (6
e - 9) years; (b) 3 years
