Howard is
g years old. Sean is six times as old as Howard and Luke is 6 years younger than Sean.
- Express Luke's age in terms of g.
- Howard is 8 years old as of now. ln how many years' time will Luke be 3 times as old as Howard?
(a)
Howard's age =
g years
Sean's age = 6
g years
Luke's age = (6
g - 6) years
(b)
g = 8
Difference in age remains unchanged.
Difference in age between Luke and Howard
= (6
g - 6) -
g = 6
g -
g - 6
= 5
g - 6
= 5 x 8 - 6
= 34 years
Difference in the age when Luke will be 3 times as old as Howard
= 3 u - 1 u
= 2 u
2 u = 34
1 u = 34 ÷ 2 = 17
Number of years' time so Luke will be 3 times as old as Howard
= 17 - 8
= 9 years
Answer(s): (a) (6
g - 6) years; (b) 9 years
