Luke is
j years old. Caden is six times as old as Luke and Jenson is 11 years younger than Caden.
- Express Jenson's age in terms of j.
- Luke is 7 years old as of now. ln how many years' time will Jenson be 3 times as old as Luke?
(a)
Luke's age =
j years
Caden's age = 6
j years
Jenson's age = (6
j - 11) years
(b)
j = 7
Difference in age remains unchanged.
Difference in age between Jenson and Luke
= (6
j - 11) -
j = 6
j -
j - 11
= 5
j - 11
= 5 x 7 - 11
= 24 years
Difference in the age when Jenson will be 3 times as old as Luke
= 3 u - 1 u
= 2 u
2 u = 24
1 u = 24 ÷ 2 = 12
Number of years' time so Jenson will be 3 times as old as Luke
= 12 - 7
= 5 years
Answer(s): (a) (6
j - 11) years; (b) 5 years
