Elijah is
p years old. David is six times as old as Elijah and Eric is 8 years younger than David.
- Express Eric's age in terms of p.
- Elijah is 8 years old as of now. ln how many years' time will Eric be 3 times as old as Elijah?
(a)
Elijah's age =
p years
David's age = 6
p years
Eric's age = (6
p - 8) years
(b)
p = 8
Difference in age remains unchanged.
Difference in age between Eric and Elijah
= (6
p - 8) -
p = 6
p -
p - 8
= 5
p - 8
= 5 x 8 - 8
= 32 years
Difference in the age when Eric will be 3 times as old as Elijah
= 3 u - 1 u
= 2 u
2 u = 32
1 u = 32 ÷ 2 = 16
Number of years' time so Eric will be 3 times as old as Elijah
= 16 - 8
= 8 years
Answer(s): (a) (6
p - 8) years; (b) 8 years
