Beverage Dispenser S and Beverage Dispenser T have a total amount of 4401 mℓ of water. For Beverage Dispenser T and Beverage Dispenser U, the total amount of water is 4806 mℓ. The amount of water in Beverage Dispenser S is ⁵₈ the amount of water in Beverage Dispenser U. What is the average amount of water in the 3 beverage dispensers?
Beverage Dispenser S = 5 u
Beverage Dispenser U = 8 u 

Beverage Dispenser T + Beverage Dispenser S = 4401 --- (1)
Beverage Dispenser T + Beverage Dispenser U = 4806 --- (2)

(2) - (1)
(Beverage Dispenser T + Beverage Dispenser S) - (Beverage Dispenser T + Beverage Dispenser U) = 4806 - 4401
8 u - 5 u = 405
3 u = 405

1 u = 405 ÷ 3 = 135
Beverage Dispenser S = 5 u = 135 x 5 = 675

Beverage Dispenser S + Beverage Dispenser T + Beverage Dispenser U = 675 + 4806 = 5481 mℓ

Average amount of water in the 3 beverage dispensers
= 5481 ÷ 3 
= 1827 mℓ

Answer(s): 1827 mℓ