A rectangular container 110 cm by 50 cm by 43 cm was 20% filled with water. A tap was turned on to fill it up with water at a rate of 10 ℓ/min. Every 15 seconds after the tap was turned on, an iron ball of volume 500 cm3 was added to the container. How many iron balls of the same volume would there be in the container when the container is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 20%
= 80%
Volume of space in the container
= 80% x 110 x 50 x 43
=
80100 x 110 x 50 x 43
= 189200 cm
3 1 ℓ = 1000 mℓ
10 ℓ = 10 x 1000 = 10000 mℓ
Number of sets of 15 seconds in 1 min
= 60 ÷ 15
= 4
Water flowed in every 15 seconds
= 10000 ÷ 4
= 2500 mℓ
Total volume added for every 15 seconds
= 2500 + 500
= 3000 cm
3 Number of sets of 3000 cm
3= 189200 ÷ 3000
= 63 r 200
After the last iron ball is added, 200 cm
3 of water will flow into the tank so that the container is 100% filled with water.
Number of iron balls added = 63
Answer(s): 63
