A rectangular container 110 cm by 60 cm by 43 cm was 10% filled with water. A tap was turned on to fill it up with water at a rate of 7 ℓ/min. Every 30 seconds after the tap was turned on, an iron ball of volume 500 cm3 was added to the container. How many iron balls of the same volume would there be in the container when the container is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 10%
= 90%
Volume of space in the container
= 90% x 110 x 60 x 43
=
90100 x 110 x 60 x 43
= 255420 cm
3 1 ℓ = 1000 mℓ
7 ℓ = 7 x 1000 = 7000 mℓ
Number of sets of 30 seconds in 1 min
= 60 ÷ 30
= 2
Water flowed in every 30 seconds
= 7000 ÷ 2
= 3500 mℓ
Total volume added for every 30 seconds
= 3500 + 500
= 4000 cm
3 Number of sets of 4000 cm
3= 255420 ÷ 4000
= 63 r 3420
After the last iron ball is added, 3420 cm
3 of water will flow into the tank so that the container is 100% filled with water.
Number of iron balls added = 63
Answer(s): 63