A rectangular container 110 cm by 40 cm by 42 cm was 10% filled with water. A tap was turned on to fill it up with water at a rate of 6 ℓ/min. Every 10 seconds after the tap was turned on, an iron ball of volume 200 cm3 was added to the container. How many iron balls of the same volume would there be in the container when the container is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 10%
= 90%
Volume of space in the container
= 90% x 110 x 40 x 42
=
90100 x 110 x 40 x 42
= 166320 cm
3 1 ℓ = 1000 mℓ
6 ℓ = 6 x 1000 = 6000 mℓ
Number of sets of 10 seconds in 1 min
= 60 ÷ 10
= 6
Water flowed in every 10 seconds
= 6000 ÷ 6
= 1000 mℓ
Total volume added for every 10 seconds
= 1000 + 200
= 1200 cm
3 Number of sets of 1200 cm
3= 166320 ÷ 1200
= 138 r 720
After the last iron ball is added, 720 cm
3 of water will flow into the tank so that the container is 100% filled with water.
Number of iron balls added = 138
Answer(s): 138