A rectangular container 110 cm by 50 cm by 45 cm was 30% filled with water. A tap was turned on to fill it up with water at a rate of 6 ℓ/min. Every 20 seconds after the tap was turned on, an iron ball of volume 500 cm3 was added to the container. How many iron balls of the same volume would there be in the container when the container is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 30%
= 70%
Volume of space in the container
= 70% x 110 x 50 x 45
=
70100 x 110 x 50 x 45
= 173250 cm
3 1 ℓ = 1000 mℓ
6 ℓ = 6 x 1000 = 6000 mℓ
Number of sets of 20 seconds in 1 min
= 60 ÷ 20
= 3
Water flowed in every 20 seconds
= 6000 ÷ 3
= 2000 mℓ
Total volume added for every 20 seconds
= 2000 + 500
= 2500 cm
3 Number of sets of 2500 cm
3= 173250 ÷ 2500
= 69 r 750
After the last iron ball is added, 750 cm
3 of water will flow into the tank so that the container is 100% filled with water.
Number of iron balls added = 69
Answer(s): 69