A rectangular tank 110 cm by 50 cm by 50 cm was 30% filled with water. A tap was turned on to fill it up with water at a rate of 9 ℓ/min. Every 20 seconds after the tap was turned on, an iron ball of volume 600 cm3 was added to the tank. How many iron balls of the same volume would there be in the tank when the tank is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 30%
= 70%
Volume of space in the tank
= 70% x 110 x 50 x 50
=
70100 x 110 x 50 x 50
= 192500 cm
3 1 ℓ = 1000 mℓ
9 ℓ = 9 x 1000 = 9000 mℓ
Number of sets of 20 seconds in 1 min
= 60 ÷ 20
= 3
Water flowed in every 20 seconds
= 9000 ÷ 3
= 3000 mℓ
Total volume added for every 20 seconds
= 3000 + 600
= 3600 cm
3 Number of sets of 3600 cm
3= 192500 ÷ 3600
= 53 r 1700
After the last iron ball is added, 1700 cm
3 of water will flow into the tank so that the tank is 100% filled with water.
Number of iron balls added = 53
Answer(s): 53