A rectangular tank 90 cm by 50 cm by 48 cm was 10% filled with water. A tap was turned on to fill it up with water at a rate of 10 ℓ/min. Every 30 seconds after the tap was turned on, an iron ball of volume 200 cm3 was added to the tank. How many iron balls of the same volume would there be in the tank when the tank is 100% filled with water?
Percentage of volume of space to be filled
= 100% - 10%
= 90%
Volume of space in the tank
= 90% x 90 x 50 x 48
=
90100 x 90 x 50 x 48
= 194400 cm
3 1 ℓ = 1000 mℓ
10 ℓ = 10 x 1000 = 10000 mℓ
Number of sets of 30 seconds in 1 min
= 60 ÷ 30
= 2
Water flowed in every 30 seconds
= 10000 ÷ 2
= 5000 mℓ
Total volume added for every 30 seconds
= 5000 + 200
= 5200 cm
3 Number of sets of 5200 cm
3= 194400 ÷ 5200
= 37 r 2000
After the last iron ball is added, 2000 cm
3 of water will flow into the tank so that the tank is 100% filled with water.
Number of iron balls added = 37
Answer(s): 37