The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube L and Cube M. The tank is filled with some water. Cube L is ³₄ filled with 41154 mℓ of water while Cube M is completely filled with water. The height of the water level in Cube L is 9 cm higher than that in Cube M. Water is then drained from the tank and the height of the new water level is 4 cm. What is the volume of the water drained in mℓ?
³₄ of the volume of Cube L = 41154 mℓ

Volume of Cube L
= 41154 ÷ ³₄
= 41154 x ⁴₃
= 54872 mℓ

Length of Cube L
= ³√54872
= 38 cm 

Height of water in Cube L at first
= ³₄ x 38
= 28.5 cm

Height of Cube M
= 28.5 - 9
= 19.5 cm

Height decrease in water in Cube L after draining
= 28.5 - 4
= 24.5 cm

Height decrease in water in Cube L after draining
= 19.5 - 4
= 15.5 cm

Volume of water drained in Cube L
= 38 x 38 x 24.5
= 35378 mℓ

Volume of water drained in Cube M
= 19.5 x 19.5 x 15.5
= 5893.875 mℓ

Total volume of water drained
= 35378 + 5893.875
= 41271.875 mℓ

Answer(s): 41271.875 mℓ