The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube P and Cube Q. The tank is filled with some water. Cube P is ³₄ filled with 73002 mℓ of water while Cube Q is completely filled with water. The height of the water level in Cube P is 6 cm higher than that in Cube Q. Water is then drained from the tank and the height of the new water level is 6 cm. What is the volume of the water drained in mℓ?
³₄ of the volume of Cube P = 73002 mℓ

Volume of Cube P
= 73002 ÷ ³₄
= 73002 x ⁴₃
= 97336 mℓ

Length of Cube P
= ³√97336
= 46 cm 

Height of water in Cube P at first
= ³₄ x 46
= 34.5 cm

Height of Cube Q
= 34.5 - 6
= 28.5 cm

Height decrease in water in Cube P after draining
= 34.5 - 6
= 28.5 cm

Height decrease in water in Cube P after draining
= 28.5 - 6
= 22.5 cm

Volume of water drained in Cube P
= 46 x 46 x 28.5
= 60306 mℓ

Volume of water drained in Cube Q
= 28.5 x 28.5 x 22.5
= 18275.625 mℓ

Total volume of water drained
= 60306 + 18275.625
= 78581.625 mℓ

Answer(s): 78581.625 mℓ