The figure is not drawn to scale. It shows a tank made from two connected cubical containers, Cube U and Cube V. The tank is filled with some water. Cube U is ²₃ filled with 13122 mℓ of water while Cube V is completely filled with water. The height of the water level in Cube U is 9 cm higher than that in Cube V. Water is then drained from the tank and the height of the new water level is 7 cm. What is the volume of the water drained in mℓ?
²₃ of the volume of Cube U = 13122 mℓ

Volume of Cube U
= 13122 ÷ ²₃
= 13122 x ³₂
= 19683 mℓ

Length of Cube U
= ³√19683
= 27 cm 

Height of water in Cube U at first
= ²₃ x 27
= 18 cm

Height of Cube V
= 18 - 9
= 9 cm

Height decrease in water in Cube U after draining
= 18 - 7
= 11 cm

Height decrease in water in Cube U after draining
= 9 - 7
= 2 cm

Volume of water drained in Cube U
= 27 x 27 x 11
= 8019 mℓ

Volume of water drained in Cube V
= 9 x 9 x 2
= 162 mℓ

Total volume of water drained
= 8019 + 162
= 8181 mℓ

Answer(s): 8181 mℓ